By definition, the roots of a quadratic function can be found using an equation of the form:
![x = (-b+/-√(b^2 - 4ac))/(2a)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/amnjym6h2hyy8l6im228un6696b6048f8p.png)
The discriminant is the following part of the expression:
![b^2 - 4ac](https://img.qammunity.org/2019/formulas/mathematics/college/fw0m5xuzewwupd1jq809xzsnjnnxh71uuz.png)
Therefore, we have three cases:
Case 1:
![b ^ 2 - 4ac\ \textgreater \ 0](https://img.qammunity.org/2019/formulas/mathematics/middle-school/vkmmsk1v82f3d3b3b31k9dktzhks6zq2jt.png)
Then there are two real solutions
Case 2:
![b ^ 2 - 4ac = 0](https://img.qammunity.org/2019/formulas/mathematics/middle-school/kc3knxnwiqy8hxsre33pu3rb9ydz1wmc5l.png)
Then there is a real solution with multiplicity two
Case 3:
![b ^ 2 - 4ac \ \textless \ 0](https://img.qammunity.org/2019/formulas/mathematics/middle-school/jemx2gcnxcfvmz3h5npz2977qelkzgiuec.png)
There are no real solutions
When the graph of a quadratic equation has no cut points with the x axis, then we are in case number 3.
Answer:
B. Negative
![b ^ 2 - 4ac \ \textless \ 0](https://img.qammunity.org/2019/formulas/mathematics/middle-school/jemx2gcnxcfvmz3h5npz2977qelkzgiuec.png)