Question

The sum of three consecutive consecutive integers is 141 what is the smallest integer

Answer 1

Let x=the smallest integer, x+1=the second smallest, x+2=the greatest.
x+x+1+x+2=141
3x+3=141
3x=138
x=46
46 is the smallest integer

Answer 2

Our three consecutive integers can be represented as

X → first integer

X + 1 → second integer

X + 2 → third integer

If the sum of our three consecutive integers is 141, our equation will read...

X + X + 1 + X + 2 = 141

Now, we can simplify on the left. Once we simplify, our equation will now read

3x + 3 = 141

-3 -3 ← subtract 3 on both sides

3x = 138 ← divide by 3 on both sides

X = 46 ← smallest integer

Therefore, the smallest integer is 46.