The answer to this question is 13 grams.
We have 11 grams of N2 and we must convert to moles in order to use stoichiometry. The molar mass of N2 is 14 * 2 = 28 g / mol. The moles of N2 are
moles N2 = 11 g N2 * (1 mol N2)/(28 g N2)
= 0.392857 mol N2
Comparing with the balanced chemical equation coefficients, we use the ratio to convert to moles of NH3:
moles NH3 = moles N2 * (2 NH3) / (1 N2)
= 0.392857 * (2) / (1)
= 0.785714 mol NH3
Converting back to grams, the molar mass of NH3 is 14 + 3(1) = 17 g / mol so
grams NH3 = 0.785714 mo * 17 g / mol
= 13 g
The answer to this question is 13 grams.