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PLEASE HELP !!!!! AND EXPLAIN . I don’t understand this that well

Find the value of the following expression: (2^8 • 5^5 • 19^0)^-2 • (5^-2 over 2^3)^4 • 2^28 answer in simplified form and please show me the steps !

User Ibaneight
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{( {2}^(8) * {5}^(5) * {19}^(0)}) ^( - 2) * {( \frac{ {5}^( - 2) }{ {2}^(3) } )}^(4) * {2}^(28) \\ \frac{(1) * ( {5}^( - 8)) * ( {2}^(28) )}{ {( {2}^(8) * {5}^(5) * 1)} ^(2) * ( {2}^(12)) }
First, we see that everything is multiplied or divided, so we can combine everything into one large fraction.
We can recognize that anything with the exponent 0 equals 1, so 19^0=1.
Since (2^8 × 5^-8 × 19^0) is to the power of -2, we can change the -2 to a 2 and put it in the denominator.
When 5^-2 and 2^3 are to the power of 4, we multiply the exponents. -2 × 4 = -8 and 3 × 4 = 12, so we put 5^-8 in the numerator, and 2^12 In the denominator.
2^28 goes in the numerator.


\frac{ {5}^( - 8)* {2}^(28) }{ {2}^(16) * {5}^(10) * {2}^(12) } \\ \frac{ {2}^(28) }{ {2}^(28) * {5}^(10) * {5}^(8) }
We can get rid of the 1s, since multiplying by 1 does not change any number.
We can factor in the exponent of 2 into (2^8 × 5^5) by multiplying 8 × 2 = 16 and 5 × 2 = 10. The new values are 2^16 and 5^10.
We can move the 5^-8 to the denominator and change it to 5^8.
We van combine 2^16 and 2^12 by adding the exponents.


\frac{1}{ {5}^(18) } \\ {5}^( - 18)
We can see that there is 2^28 in the numerator, and 2^28 in the denominator, so we can subtract them. Since 28 - 28 = 0, we can eliminate both of them.
We can combine 5^10 and 5^8 to get 5^18.
1 over 5^18 is also equal to 5^-18.

Depending on what your teacher is looking for, the answer is one of those two.
User James Ruskin
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