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Which function’s domain consists of all real numbers greater than 3?

A) f(x) = 3x

B) f(x) = the square root of x

C) f(x) = 3x + 4

D) f(x) = 1 over the square root of x - 3

User Gokul NC
by
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2 Answers

1 vote
Correct answer is D).
A) and C) are polynomials, so x∈R, in B) we have √x, and in this case x ≥ 0.
User Mike Ubezzi
by
8.7k points
2 votes

Answer:


f(x)=(1)/(x-3)

Explanation:

find function that consist of domain = all real numbers greater than 3

A)
f(x) = 3x

f(x) is a linear function, for all linear function the domain is set of all real numbers.

B)
f(x)= √(x)

For square root function , the domain is set of all real numbers greater than 0

C)
f(x) = 3x + 4

f(x) is a linear function, for all linear function the domain is set of all real numbers.

D)
f(x)=(1)/(x-3)

for square root function we set x-3>0 and solve for x

x > 3, so domain is all real numbers greater than 3

User Peter Moresi
by
7.5k points

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