Simplify the complex fraction. y-1/y^2+y-6/y-6/y+3 A) (y-1)(y-2)/(y-6)(y+2) B) y-1/(y-6)(y-2) C) (y-1)(y-6)/(y+3)^2 (y-2) D) (y-1)(y-6)/(y+3)(y-2) I really need help on this

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asked Jan 12, 2019 165k views

2 Answers

Piotrga · Answer 1 · 2019-01-19T00:29:49+0000

For this case we have the following complex fraction:

((y-1)/(y^2+y-6) )/((y-6)/(y+3))

Using the double C method, we can rewrite the given fraction.
We have then:

((y-1)(y+3))/((y^2+y-6)(y-6))

Then, we must factor the quadratic expression into the denominator.
We have then:

((y-1)(y+3))/((y-2)(y+3)(y-6))

Finally, we cancel similar terms.
We have then:

((y-1))/((y-2)(y-6))

Answer:
the complex fraction simplified is:
B) y-1/(y-6)(y-2)