answer : False
The measure of a tangent-tangent angle is one - half the difference of the measures of the intercepted arcs.
The diagram is attached below
AB and BC are the two tangents
By exterior angle theorem
∠3 = ∠2 + ∠4
So ∠2 = ∠3 - ∠4
Now we find angle 3 and 4, we know when a chord and tangent intersect at a point then the measure of angle is one half of measure of intercepted arc
∠3 =
∠4 =
![(1)/(2) * arc(AC)](https://img.qammunity.org/2019/formulas/mathematics/college/th7m1tgfrq2c823qg9zomk5mqmjl2sx3sq.png)
∠2 = ∠3 - ∠4
∠2 =
-
![(1)/(2) * arc(AC)](https://img.qammunity.org/2019/formulas/mathematics/college/th7m1tgfrq2c823qg9zomk5mqmjl2sx3sq.png)
∠2 =
![(1)/(2) ( arc(ADC) - arc(AC))](https://img.qammunity.org/2019/formulas/mathematics/college/izb8jchzmhky71i2i51szkfmqcxn45ez3x.png)
The measure of a tangent-tangent angle is one half the difference of the measures of the intercepted arcs.