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1 vote
Express 3^2 = x as a logarithmic equation.

log3x = 2

log32 = x

log23 = x

log2x = 3

1 Answer

4 votes
Taking the log of both sides of the equation, you have

2\log(3)=\log(x)
Dividing by log(3), this looks like the change of base formula.

\log_a(b)=(\log(b))/(\log(a))

That is, division by log(3) gives

2=(\log(x))/(\log(3))\\\\2=log_3(x)

This apparently matches your first choice:
log3(x) = 2
User CornPuff
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