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The simplest form of the expression 4m-17/m^2-16 + 3m-11/m^2-16 has ____in the numerator and___ in the denominator.

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For this case we have the following expression:

(4m-17)/(m^2-16) + (3m-11)/(m^2-16)
Since the denominator is equal, then we can add the numerator.
We have then:

((4m-17) + (3m-11))/(m^2-16)
Adding similar terms we have:

((4m+3m) + (-17-11))/(m^2-16)
Rewriting we have:

(7m - 28)/(m^2-16)
Doing common factor in the numerator we have:

(7(m - 4))/(m^2-16)
Factoring the denominator we have:

(7(m - 4))/((m-4)(m+4))
Canceling similar terms we have:

(7)/(m+4)
Answer:
The simplest form of the expression has 7 in the numerator and m+4 in the denominator.
User Roostaamir
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