The simplest form of the expression 4m-17/m^2-16 + 3m-11/m^2-16 has __in the numerator and_ in the denominator.

Question

asked Mar 8, 2019 221k views

1 Answer

Roostaamir · Answer 1 · 2019-03-13T22:14:00+0000

For this case we have the following expression:

(4m-17)/(m^2-16) + (3m-11)/(m^2-16)

Since the denominator is equal, then we can add the numerator.
We have then:

((4m-17) + (3m-11))/(m^2-16)

Adding similar terms we have:

((4m+3m) + (-17-11))/(m^2-16)

Rewriting we have:

(7m - 28)/(m^2-16)

Doing common factor in the numerator we have:

(7(m - 4))/(m^2-16)

Factoring the denominator we have:

(7(m - 4))/((m-4)(m+4))

Canceling similar terms we have:

(7)/(m+4)

Answer:
The simplest form of the expression has 7 in the numerator and m+4 in the denominator.