Given:(x₁,y₁) = (1,5)
(x₂,y₂) = (3,11)
Solution:First, determine the slope of the line with slope formula
m =
![(y_(2)-y_(1))/(x_(2)-x_(1))](https://img.qammunity.org/2019/formulas/mathematics/middle-school/565g05mtntw6wr2a6eupap1r4fv5i7auo1.png)
m =
![(11-5)/(3-1)](https://img.qammunity.org/2019/formulas/mathematics/high-school/ftjvl8by7bl7htbo80mzxw1e8iyqpi94yt.png)
m =
![(6)/(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/tyed73b7fleeik34k25qytuor18sj28lz6.png)
m = 3
Second, substitute the value of the slope m and one of the points to the formula of line equation below
y - y₁ = m(x - x₁)
y - 5 = 3(x - 1)
y - 5 = 3x - 3
3x - 3 = y - 5
3x - y = -5 + 3
3x - y = -2
This is standard form of a line