Question

`x {}^(2) + 2x + 6 = 0`
please give me answer.....​

Answer 1

`\sf x = -1 + √(5)\:i,\: -1 - √(5)\:i`

Step-by-step explanation:

`\sf \rightarrow x^2 + 2x +6 = 0`

`\sf use\:quadratic\:formula: x = ( -b \pm √(b^2 - 4ac))/(2a) \quad when \: \: ax^2 + bx + c = 0`

comparing identify:

• a = 1, b = 2, c = 6

Substitute inside the formula:

`\rightarrow \sf x = ( -2 \pm √(2^2 - 4(1)(6)))/(2(1))`

evaluate:

`\rightarrow \sf x = ( -2 \pm √(4 - 24))/(2)`

`\rightarrow \sf x = ( -2 \pm √(- 20))/(2)`

`\rightarrow \sf x = ( -2 \pm 2√(5)\:i)/(2)`

`\rightarrow \sf x =-1 \pm √(5)\:i`

`\rightarrow \sf x = -1 + √(5)\:i,\: -1 - √(5)\:i`