Question

I need help with question 4. a)

Answer 1

`\bf 4(2x-1)^2=36\implies (2x-1)^2=\cfrac{36}{4}\implies (2x-1)^2=9 \\\\\\ √((2x-1)^2)=√(9)\implies 2x-1=\pm 3\implies 2x = \pm 3 +1 \\\\\\ x=\cfrac{\pm 3 +1}{2}\implies x= \begin{cases} \cfrac{4}{2}\implies &2\\\\ \cfrac{-2}{2}\implies &-1 \end{cases}`