Answer: The given sequence is a GEOMETRIC sequence with first term 7 and common ratio 2.
Step-by-step explanation: We are given to define the type of the following sequence :
7, 14, 28, 56, 122, . . .
Let us denote the n-th ter of the given sequence by
![a_n.](https://img.qammunity.org/2019/formulas/mathematics/middle-school/teo9k46ymiigshguy1wxnitbdrvmi3sq09.png)
Then, we see the following relation between the consecutive terms of the given sequence :
![(a_2)/(a_1)=(14)/(7)=2,\\\\\\(a_3)/(a_2)=(28)/(14)=2,\\\\\\(a_4)/(a_3)=(56)/(28)=2,\\\\\\(a_5)/(a_4)=(122)/(56)=2,\\\\\\\vdots~~~~~~\vdots](https://img.qammunity.org/2019/formulas/mathematics/middle-school/qlv8ml3st4miqf5mc3u4faxick0pj35fr1.png)
Therefore, we get
![(a_2)/(a_1)=(a_3)/(a_2)=(a_4)/(a_3)=(a_5)/(a_4)=~~.~~.~~.~~=2.](https://img.qammunity.org/2019/formulas/mathematics/middle-school/2cbjx1dclw8m0n1l0jppboozavgqn7v1wy.png)
That is, there is a common ratio of 2 between any two consecutive terms of the sequence.
Thus, the given sequence is a GEOMETRIC sequence with first term 7 and common ratio 2.