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4 votes
Determine the zeros of the function f(x) = 3x^2 -7x+1

2 Answers

4 votes

Answer:

x=7+_ sqrt of 37 over 6

Explanation:

User Florent Bayle
by
8.0k points
4 votes
I will use the quadratic formula.


\text{The zeros of function:}\ f(x)=0\\\\f(x)=3x^2-7\\\\f(x)=0\to3x^2-7x+1=0\\\\a=3;\ b=-7;\ c=1\\\\b^2-4ac=(-7)^2-4\cdot3\cdot1=49-12=37\\\\x_1=(-b-√(b^2-4ac))/(2a);\ x_2=(-b+√(b^2-4ac))/(2a)\\\\x_1=(-(-7)-√(37))/(2\cdot3)=(7-√(37))/(6)\\\\x_2=(-(-7)+√(37))/(2\cdot3)=(7+√(37))/(6)

User Jazzie
by
7.9k points

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