Question

Determine the zeros of the function f(x) = 3x^2 -7x+1

Answer 1

x=7+_ sqrt of 37 over 6

Explanation:

Answer 2

I will use the quadratic formula.


`\text{The zeros of function:}\ f(x)=0\\\\f(x)=3x^2-7\\\\f(x)=0\to3x^2-7x+1=0\\\\a=3;\ b=-7;\ c=1\\\\b^2-4ac=(-7)^2-4\cdot3\cdot1=49-12=37\\\\x_1=(-b-√(b^2-4ac))/(2a);\ x_2=(-b+√(b^2-4ac))/(2a)\\\\x_1=(-(-7)-√(37))/(2\cdot3)=(7-√(37))/(6)\\\\x_2=(-(-7)+√(37))/(2\cdot3)=(7+√(37))/(6)`