Question

I have the inequality 120A + 100B <= 220 how do i graph this?

Answer 1

Change the equation to slope intercept form.

(y= 1.2x + 2.2) or (b= 1.2a + 2.2)

Then shade above the line.

Explanation:

Let's say A is "x", and B is "y."

Change the equation to slope intercept form.

120x + 100y = 220.

(Move 120x to the other side of the equation by subtracting 120x from both sides)

100y= -120x +220

(Divide 100y by 100 to remove it from Y, divide the entire right side of the equation by 100)

y= -120x/100 + 220/100

y <= 1.2x + 2.2 -> (b= 1.2a + 2.2)

The new equation is much easier to graph.

THEN, Plot the new equation, since the sign is <= (greater than or equal to)

Make a solid line.

Then shade above the line whatever color necessary, since the sign is also "greater than"

Answer 2

See below

Explanation:

Given inequality

• 120a + 100b ≤ 220

This is a linear inequality, to graph first find intercepts:

a- intercept, when b = 0

• 120a = 220
• a = 220/120 = 1.833

b- intercept, when a = 0

• 100b = 220
• b = 220/100 = 2.2

We got two points:

• (1.833, 0) and (0, 2.2)

Now graph this with following steps

• 1. Plot these points on the coordinate plane.
• 2. Construct a solid line passing through those two points. (it would be dotted line is inequality sigh was > or < )
• 3. Shade the area left to the line. (it would be the area to right if inequality sign was ≥)

The graph is attached