Question

a gas has volume of 237.54mlnwhen measured at 45°C if the temperature changed to 65°C what would be the new volume

Answer 1

Hello!

Data:

Vo (initial volume) = 237.54 mL
V (final volume) = ?
To (initial temperature) = 45 ºC (to Kelvin)
T (final temperature) = 65 ºC (to Kelvin)
Note: In gas studies the Kelvin scale (K) is used
To (initial temperature) = TC + 273
To (initial temperature) = 45 + 273
To (initial temperature) = 318

T (final temperature) = TC + 273
T (final temperature) = 65 + 273
T (final temperature) = 338

We have an isobaric transformation, that is, its pressure remains constant, if it increases the temperature the volume also increases, applying the data to the formula, we have:


`(V_0)/(T_0) = (V)/(T)`


`(273.54)/(318) = (V)/(338)`


`318*V = 273.54*338`


`318V = 92456.52`


`V = (92456.52)/(318)`


`\boxed{\boxed{V \approx 290.74\:mL}}\end{array}}\qquad\checkmark`

I hope this helps. =)