Answer:
The point which lies on a side of the pre-image, square RSTU is:
(-1,-6)
Explanation:
We are given that Square RSTU is translated to form R'S'T'U', which has vertices R'(–8, 1), S'(–4, 1), T'(–4, –3), and U'(–8, –3).
Also the vertices of point S are (3,-5).
So let the translation is carried out by the rule:
(x,y) → (x+a,y+b)
That means all the points are translated by the same rule.
We let S(x,y)=(3,-5).
and S'(x,y)=(-4,1)
i.e. (3+a,-5+b)=(-4,1)
i.e. 3+a=-4 and -5+b=1
i.e. a=-7 and b=6
Hence the translation is defined as:
(x,y) → (x-7,y+6)
Hence the pre-image for any point (x',y') will be:
(x'+7,y'-6)
The coordinates of R given that the coordinates of R'(-8,1) is: (-8+7,1-6)=(-1,-5)
Coordinates T are given that coordinates of T'(-4,-3) are: (-4+7,-3-6)=(3,-9)
Coordinates U are given that coordinates of U'(-8,-3) are: (-8+7,-3-6)=(-1,-9)
Hence the vertex of rectangle RSTU are:
R(-1,-5) , S(3,-5) , T(3,-9) and U(-1,-9)
Now we graph this rectangle and also plot the given points in the options and see which point lie on the side of the rectangle RSTU.
The answer is:
(-1,-6)