Since each term of the series is 1.1 times the previous one, the series is geometric. The generic term of a geometric series is

The sum in sigma notation simply adds these terms. The leading factor of 100 can be factored out.

The sum can be found by adding the terms or by using the formula for the sum of a geometric series. In the latter case, we have

The series is divergent because the common ratio of terms is greater than 1. (Of course, any finite number of terms will have a finite sum.)