What is the volume occupied by 3.70 moles of n2 gas at stp?

Question

asked Jun 22, 2019 56.4k views

1 Answer

Tal Barda · Answer 1 · 2019-06-26T06:03:49+0000

The conversion factor for volume at STP is
$\frac {1mol}{22.4L}$ or
(22.4L)/(1mol)

. Since we want volume, we would use
(22.4L)/(1mol)

. We conclude with the following calculations:

$3.70molN_(2) * \frac {22.4LN_(2)}{1mol N_(2)} = 82.88LN_(2)$

The answer is 82.88L N2