Answer:
Explanation:
Given is a regular hexagon with apothem 3 square root 3 mm.
We have hexagon regular can be divided into 6 equilateral triangles with common vertex at the centre of the hexagon
Each equilateral triangle will have
as apothem
Hence using equilateral triangle property
we have side = a (say)
Then
![√(3) (a)/(2) =3√(3) \\Or a = 6](https://img.qammunity.org/2019/formulas/mathematics/high-school/dslw3jwiz3jbmxp34rx8crgzt4fkltcq20.png)
Area of each triangle = 1/2 bh = 9 sqrt 3
Hence area of hexagon =
![6(9√(3))=54√(3)](https://img.qammunity.org/2019/formulas/mathematics/high-school/r6ir3unbslequsjys9s1o0bjamhsy31zwa.png)
Use sqroot 3 = 1.732
we get
93.53 square mm.