198k views
0 votes
Graph the first six terms of a sequence where a1=5 and r=1.25

User GingerBeer
by
8.7k points

1 Answer

4 votes
The sequence above is geometric progression.
The nth term of such sequence is given by;

Tn = ar∧(n-1),
Where a⇒first term and
r⇒common ratio

So, 1st term = 5×1.25∧(1-1) = 5×1.25∧0 =5
2nd term = 5×1.25∧(2-1) = 5×1.25 = 6.25
3rd term = 5×1.25∧(3-1) = 5×1.25² = 7.8125
4th term = 5×1.25∧(4-1) =5×1.25³ = 9.765625
5th term = 5×1.25∧(5-1) = 5×1.25∧4 = 12.20703125
6th term = 5×1.25∧(6-1) = 5×1.25∧5 = 15.25878909
User Hille
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories