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The area of the tympanic membrane is 100 mm 2 and the area of the oval window is 5 mm 2 . if a sound wave applies 10 n to the tympanic membrane and the pressure is transmitted, unaltered, to the oval window, how much force is applied to the oval window?

1 Answer

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The answer is "0.5N".


According to the question;
P1=P2
so,
F1/A1= F2/A2

P=(F/A)

A1=100mm²

F1= 10N

A2= 5mm
²

F2= ?

F2= ((F1 x A2)/A1)
= ((10 x 5) /100)

=50/100

=0.5N
User Shikhar Mishra
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