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PLEASE HELP! 12 balls numbered 1 through 12 are placed in a bin. Joe produces a list of three numbers by performing the following sequence three times: he chooses a ball, records the number, and places the ball back in the bin. How many different lists are possible?

User Borncrazy
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2 Answers

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12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 479,001,600

I recommend you use this as a starter. I can't be completely sure if it's right. I hope it helps though! Good luck!
2 votes

Answer:

12*12*12=1728

Explanation:

permutations

since balls can be repeated it is 12 12 12

User Cwiggo
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