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There are 6 boys and 6 girls in a room. what is the probabilitythat the two children chosen at random will be one girl and one boy?

1 Answer

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P(first is a boy) = 6/12 = 1/2
P(second is a girl) = 6/11

P(first boy then a girl) = 1/2 * 6/11 = 6/22 = 3/11

by a similar process P( girl then a boy) = 3/11

So the required probability = 3/11 + 3/11 = 6/11 Answer
User Felixthehat
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