The figure is composed by 2 Isosceles Triangles (Two equal sides) and one Rectangle in the middle.
Triangle Area:
![base * height / 2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/tvept497rl8y1rwlaaqcxmz05agmcb5f3j.png)
Rectangle Area:
![length * width](https://img.qammunity.org/2019/formulas/mathematics/middle-school/9y4q9a1ulbm2jx6d2lshtpbqfktqrb2ta2.png)
- Triangles:
Base: 16cm
Height: 6cm
- Rectangle:
Length: 16cm
Width: 10cm
Triangle Area (At):
- At = 16 x 6/2
- At = 96/2
- At = 48 cm^2
Rectangle Area (Ar):
- Ar = 16 x 10
- Ar = 160 cm^2
Total Area = 2 x (Triangle Area) + Rectangle Area
Total Area = 2 x 48 + 160
Total Area = 96 + 160
Total Area = 256cm^2
Answer: 256cm^2, last alternative.