Question

What is the standard form of the equation of a circle given by x^2 + y^2 - 18x + 8y + 5 = 0

Answer 1

x-9,y+4,92

Explanation:

Answer 2

Completing the square:


x^2 - 18x + y^2 + 8y = -5
x^2-18x +81 - 81 + y^2 + 8y + 16 - 16 = -5.

Then, (x-9)^2 + (y+4)^2 = -5 + 81 + 16 = 92

Then the desired equation is (x-9)^2 + (y+4)^2 = 92.