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What is the standard form of the equation of a circle given by x^2 + y^2 - 18x + 8y + 5 = 0
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What is the standard form of the equation of a circle given by x^2 + y^2 - 18x + 8y + 5 = 0

User Ylor
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2 Answers

3 votes

Answer:

x-9,y+4,92

Explanation:

User Jason Shantz
by
5.0k points
1 vote
Completing the square:


x^2 - 18x + y^2 + 8y = -5
x^2-18x +81 - 81 + y^2 + 8y + 16 - 16 = -5.

Then, (x-9)^2 + (y+4)^2 = -5 + 81 + 16 = 92

Then the desired equation is (x-9)^2 + (y+4)^2 = 92.
User Ekra
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