Work done can be computed using the formula:
![W=Fd](https://img.qammunity.org/2019/formulas/physics/high-school/l0gt7whtx39ssm4nmk38gmvh3cvccrnfwe.png)
Where:
W = work (J)
F = Force (N)
d = Distance (d)
Looking at the given, you know that you do not have a value for force, so you will have to solve for it.
![F = ma](https://img.qammunity.org/2019/formulas/physics/middle-school/5f5bp1hv2rrdgiu0bfj00tk5qdgslevtn0.png)
Where:
F = Force
m = mass
a = acceleration
Because the object is being lifted, the acceleration will rely on gravity. Acceleration due to gravity is a constant 9.8 m/s^2. Let's list our given first:
F = ?
m = 100kg
a = 9.8m/s^2
Put that into our equation and solve:
![F=ma](https://img.qammunity.org/2019/formulas/physics/middle-school/1fz9hgmj558w2aylxf067s9vb6qwkf1pat.png)
![F=(100kg)(9.8m/s^(2))](https://img.qammunity.org/2019/formulas/physics/high-school/opuuf4h444q7e44udve32bqg799k6gfhhm.png)
![F=980kg.m/s^(2)](https://img.qammunity.org/2019/formulas/physics/high-school/e9cufheka0j10p0gf2zj3klzytvatodrs4.png)
Our force is then
980 N.
Now that we have force we can solve for Work. The given for work is as follows:
F= 980N
d = 1.4m
Put that into our formula and solve:
![W = Fd](https://img.qammunity.org/2019/formulas/physics/high-school/exu3z78rnsyxro46o10c1alukydpnllaky.png)
![W = (980N)(1.4m)](https://img.qammunity.org/2019/formulas/physics/high-school/e3fogadj75jxl6boga5jgvvl00yu2zso6p.png)
![W = 1,372J](https://img.qammunity.org/2019/formulas/physics/high-school/3m48uxrgkvr17k6sdxyvyyie3n3h3wj41c.png)
The work done is
1,372J.