Question

If you drop a 150-gram piece of metal that has a temperature of 125° Celsius into 1000 grams of water at 20° Celsius, what best describes what would occur? (2 points)

More heat will be lost by the metal than gained by the water.

The temperature of the water will be greater than the amount of heat lost by the metal.

The temperature change of the metal will equal the temperature change of the water.

The heat lost by the metal will equal the heat gained by the water.

Answer 1

the heat lost by the metal will equal the heat gained by the water

Answer 2

Answer : The correct option is "The heat lost by the metal will be equal to heat gained by the water"

Explanation :

In the above problem we have 2 systems, metal and water . Let us find the heat for each system.

The heat, Q is calculated using following formula

`Q = m * C * \bigtriangleup T`

Here m is the mass of the substance.

C is the specific heat of the substance.

ΔT is the change in temperature.

We know that heat flows from a substance which is at higher temperature to the substance at lower temperature.

Since metal is at higher temperature it will lose heat.

The amount of heat lost by metal is

`Q_(lost) = 150 * C * (\bigtriangleup T)_(metal)`

Water is at lower temperature, therefore it will absorb the heat lost by the metal.

The heat gained by water is calculated as

`Q_(gained) = 1000 * 4.184 * (\bigtriangleup) T_(water)`

According to thermodynamic principle,

`Q_(lost) = - Q_(gained)`

That means heat lost by the metal would be equal to heat gained by the water.