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In the triangle below, what ratio is sec H?
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3 votes
In the triangle below, what ratio is sec H?

In the triangle below, what ratio is sec H?-example-1
User Mounirboulwafa
by
5.8k points

1 Answer

2 votes
we know that
in the right triangle FGH
cos H=adjacent side angle H/hypotenuse
adjacent side angle H=g
hypotenuse=f
so
cos H=g/f
sec H=1/cos H
sec H=1/(g/f)-----> sec H=f/g

the answer is
sec H=f/g
User Russell Quinn
by
6.2k points
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