In the triangle below, what ratio is sec H?

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asked Feb 22, 2019 59.4k views

1 Answer

Russell Quinn · Answer 1 · 2019-02-26T15:39:23+0000

we know that
in the right triangle FGH
cos H=adjacent side angle H/hypotenuse
adjacent side angle H=g
hypotenuse=f
so
cos H=g/f
sec H=1/cos H
sec H=1/(g/f)-----> sec H=f/g

the answer is
sec H=f/g

In the triangle below, what ratio is sec H?

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