How do you factor: #y= 2x^3 -32x #?

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asked Sep 18, 2019 144k views

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Aleksey Shevchenko · Answer 1 · 2019-09-23T16:03:49+0000

Which two factors are common to both terms of the given expression?
One of those factors is 2; the other is x.

Thus, y= 2x^3 -32x = 2x(x^2-16)

Also note that x^2-16 is easily factorable:

y = 2x(x-4)(x+4) (answer)

How do you factor: #y= 2x^3 -32x #?

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