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How do you factor: #y= 2x^3 -32x #?
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How do you factor: #y= 2x^3 -32x #?

User Wegged
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1 Answer

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Which two factors are common to both terms of the given expression?
One of those factors is 2; the other is x.

Thus, y= 2x^3 -32x = 2x(x^2-16)

Also note that x^2-16 is easily factorable:

y = 2x(x-4)(x+4) (answer)
User Aleksey Shevchenko
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