Answer:
Explanation:
I must assume that you meant y = 7(6)^(x+2) + 1.
Please use " ^ " to indicate exponentiation. Thanks.
1) Graph y = 6^x first. Its y-intercept is (0, 1). It has a horizontal asymptote in y = 0. The graph starts in Quadrant II and progresses into Quadrant I, never touching or crossing the x-axis.
2) Stretch your graph vertically by a factor of 7.
3) Translate your resulting graph up by 1 unit.
4) Translate your graph 2 units to the LEFT.