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What volume of 0.585 m ca(oh)2 would be needed to neutralize 15.8 l of 1.51 m hcl?

User Milesmeow
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1 Answer

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when the balanced reaction equation is:

2HCl(aq) + Ca(OH)2(aq) → CaCl2(aq) + 2H2O(l)

from the balanced equation, we can get the molar ratio between HCl & Ca(OH)2

2:1

∴ the volume of Ca(OH)2 = 15.8 L HCl * 1.51 m HCl * (1mol Ca(OH)2/ 2mol HCl) * (1L ca(OH)2/0.585 mol Ca(OH)2

= 20.4 L
User Googme
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