Question

For the function given, state the starting point for a sample period: ƒ(t) = 0.2sin (t − 0.3) + 0.1

Answer 1

(0.3,0.1)

Explanation:

graddy

Answer 2

The graph of this function is shown in the figure below. The general form of a sine wave is given by:


`y(t)=Asin(2 \pi ft+\Phi)+B`

A: The amplitude.

f : The ordinary frequency, the number of oscillations (cycles) that occur each second of time.

ω = 2πf, the angular frequency, the rate of change of the function argument in units of radians per second

B = the displacement in y-axis


`\Phi` = the phase, specifies (in radians) where in its cycle the oscillation is at t = 0.

The period is given by:


`T= (1)/(f)`

Therefore:


`\omega= (2 \pi )/(T)`

And givent that
`\omega= 1`, then
`T=2\pi`,

Finally, the starting point for a sample period occurrs when
`t=0`


`f(0)=0.2sin(0-0.3)+0.1=\boxed{0.04}`