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What is the equation of the line that passes through the point (5, -2)
and has a slope of 6/5

What is the equation of the line that passes through the point (5, -2) and has a slope-example-1
User Madiver
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1 Answer

7 votes

Answer:

y + 2 = ⁶/₅(x - 5) {the point-slope form of the equation}

y = ⁶/₅x - 8 {the slope-intercept form of the equation}

6x - 5y = 40 {the standard form of the equation}

Explanation:

The point-slope form of equation is: y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through and m is the slope.

m = ⁶/₅

(5, -2) ⇒ x₀ = 5, y₀ = -2

So, the point-slope form of the equation:

y + 2 = ⁶/₅(x - 5)

Therefore:

y + 2 = ⁶/₅x - 6 {subtract 2 from both sides}

y = ⁶/₅x - 8 ← the slope-intercept form of the equation

-⁶/₅x + y = - 8 {multiply both sides by (-5)}

6x - 5y = 40 ← the standard form of the equation

User Peddy
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