19.3k views
7 votes
What is the equation of the line that passes through the point (5, -2)
and has a slope of 6/5

What is the equation of the line that passes through the point (5, -2) and has a slope-example-1
User Madiver
by
8.7k points

1 Answer

7 votes

Answer:

y + 2 = ⁶/₅(x - 5) {the point-slope form of the equation}

y = ⁶/₅x - 8 {the slope-intercept form of the equation}

6x - 5y = 40 {the standard form of the equation}

Explanation:

The point-slope form of equation is: y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through and m is the slope.

m = ⁶/₅

(5, -2) ⇒ x₀ = 5, y₀ = -2

So, the point-slope form of the equation:

y + 2 = ⁶/₅(x - 5)

Therefore:

y + 2 = ⁶/₅x - 6 {subtract 2 from both sides}

y = ⁶/₅x - 8 ← the slope-intercept form of the equation

-⁶/₅x + y = - 8 {multiply both sides by (-5)}

6x - 5y = 40 ← the standard form of the equation

User Peddy
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.