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Write the sum using summation notation, assuming the suggested pattern continues. 16 + 25 + 36 + 49 + ... + n2 + ...

User Zaria
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2 Answers

5 votes

\bf \stackrel{4^2}{16}+\stackrel{5^2}{25}+\stackrel{6^2}{36}+\stackrel{7^2}{49}+...\qquad \qquad \qquad \sum\limits_(i=4)^(\infty)~i^2
User Orde
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1 vote

Answer:

Hence, the sum using summation notation, assuming the suggested pattern continues
16+25+36+49+......+n^2+..... is:


\sum_(n=4)^(\infty)n^2

Explanation:

We have to write the sum using summation notation, assuming the suggested pattern continues:


16+25+36+49+......+n^2+.....

Clearly we may also write this pattern as:


4^2+5^2+6^2+.....+n^2+......

So, in terms of the summand it is written as:


\sum_(n=4)^(\infty)n^2

( We have started our summation from 4 since the term in the summation starts with 16 which is 4^2 and goes to infinity )

User Chaosxmk
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5.2k points
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