Answer:
Hence, the sum using summation notation, assuming the suggested pattern continues
is:
![\sum_(n=4)^(\infty)n^2](https://img.qammunity.org/2019/formulas/mathematics/college/11op0t75fznsf2uogvvcwq2wq7t4s13arl.png)
Explanation:
We have to write the sum using summation notation, assuming the suggested pattern continues:
![16+25+36+49+......+n^2+.....](https://img.qammunity.org/2019/formulas/mathematics/college/askn6d8imakh3nyqozslk4u0s6ofgqfcm7.png)
Clearly we may also write this pattern as:
![4^2+5^2+6^2+.....+n^2+......](https://img.qammunity.org/2019/formulas/mathematics/college/s02s3lo3lzlkd3bde4pdn9z1prqyl6f2a5.png)
So, in terms of the summand it is written as:
![\sum_(n=4)^(\infty)n^2](https://img.qammunity.org/2019/formulas/mathematics/college/11op0t75fznsf2uogvvcwq2wq7t4s13arl.png)
( We have started our summation from 4 since the term in the summation starts with 16 which is 4^2 and goes to infinity )