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What is the sum of the arithmetic sequence 3, 9, 15..., if there are 36 terms? a. 3,468 b. 3,888 c. 4,234 d. 4,572
asked
Mar 25, 2019
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What is the sum of the arithmetic sequence 3, 9, 15..., if there are 36 terms?
a. 3,468
b. 3,888
c. 4,234
d. 4,572
Mathematics
high-school
Marcus Erronius
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Marcus Erronius
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2
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Answer:B✓
Explanation:
The answer is 3,888
Bluetoft
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Mar 25, 2019
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Bluetoft
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3
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we know that
the formula of the
the sum of the arithmetic sequence is
Sum=n*(a1+an)/2
n=36
a1=3
a36=?
find a36
an=a1+(n-1)*d
for n=2 a2=9
9=3+(2-1)*d----> 9=3+d----> d=6
so
for n=36
a36=a1+(36-1)*6----> a36=3+35*6----> a36=213
Sum=n*(a1+an)/2-----> 36*[3+213]/2----> 3888
the answer is
3888
Pragnesh Vaghela
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Mar 31, 2019
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Pragnesh Vaghela
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