Question

Evaluate (x^-2y^0)/(x^3y^-2) when x = 2 and y = 5. a. 25/2 b. 25/32 c. 50

Answer 1

The answer is B. 25/32

Answer 2

b. 25/32

Explanation:

To evaluate the function

`f(x,y) = (x^(-2)y^(0))/(x^(3)y^(-2))`

When
`x = 2, y = 5` we replace x by 2 and y by 5 in the function. So:

`f(x,y) = (x^(-2)y^(0))/(x^(3)y^(-2))`

`f(2,5) = (2^(-2)5^(0))/(2^(3)5^(-2))`

Expressions wth negative exponents in the numerator go to the denominator with positive exponent. On the denominator goes to the numerator with positive exponent. So:

`f(2,5) = (5^(2)5^(0))/(2^(3)2^(2))`

`f(2,5) = (5^(2)*1)/(8*4) = (25)/(32)`

The correct answer is

b. 25/32