Question

A 450-N rightward force is used to drag a large box across the floor with a constant velocity of 1.2 m/s. The coefficient of friction between the box and the floor is 0.795. Determine the mass of the box.

Answer 1

the mass of the box is 51.98 kg.

Step-by-step explanation:

Given;

applied horizontal force, F = 450 N

coefficient of friction, μ = 0.795

constant velocity, v = 1.2 m/s

At constant velocity, the acceleration of the object is zero and the net force will be zero.

`F_(Net) = F - F_k\\\\0 = F - F_k\\\\F_k = F\\\\\mu \ N = F\\\\\mu (mg) = F\\\\m = (F)/(\mu g) \\\\m = (405)/(0.795 \ * \ 9.8) \\\\m = 51.98 \ kg`

Therefore, the mass of the box is 51.98 kg.