2 Answers

Olinsha · Answer 1 · 2019-10-10T05:53:57+0000

Answer : Cu²⁺ ion can be most easily reduced.

Explanation :

Let us write the reduction reactions and the associated standard reduction potentials for the given ions.

1)
$Cu^(2+) + 2e^(-)\rightarrow Cu$
E^(0)_(red)= 0.34 V

2)
$Zn^(2+) + 2e^(-)\rightarrow Zn$
E^(0)_(red)= -0.76 V

3)
$Ni^(2+) + 2e^(-)\rightarrow Ni$
E^(0)_(red)= -0.26 V

4)
$Ca^(2+) + 2e^(-)\rightarrow Ca$
E^(0)_(red)= -2.87 V

If we look at the above standard reduction potential values, we see that standard reduction potential is highest for Cu²⁺ ion.

Higher the standard reduction potential, greater is the ability to undergo reduction.

Since Cu²⁺ ion has the highest standard reduction potential, it can be most easily reduced.

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