We are given Volume of the larger cylinder is = 1600 cubic centimeters.
Height of the larger cylinder = 16 cm.
We know formula of volume of a cylinder V=
, where r is the radius of cylinder, h is the height of the cylinder.
Plugging value of V and h of larger cylinder, we get
![1600=\pi r^2(16).](https://img.qammunity.org/2019/formulas/mathematics/college/lf79nceausyvf9jjdm1gvgvl8rukfvj4nt.png)
Dividing both sides by 16, we get
![(1600)/(16)=(\pi r^2 (16))/(16)](https://img.qammunity.org/2019/formulas/mathematics/college/93orkj4fi8iwg1foj68jtq94fhx6ud7ksd.png)
![r^2=100](https://img.qammunity.org/2019/formulas/mathematics/college/xu5c9x6v7sbmdojjhf2st33fgclbwcmcq4.png)
Taking square root on both sides, we get
r=10.
Therefore, radius of the larger cylinder is 10 cm.
We are given cylinders are similar .
Note: The radii and heights of similiar cylinders are in same ratio.
Therefore, we can setup a proportion:
Let us take radius of small cylinder is x.
![(x)/(10)=(4)/(16)](https://img.qammunity.org/2019/formulas/mathematics/college/2eergg2w0si664hvo6eoc5sdtr94lbs26b.png)
![(x)/(10)=(1)/(4)](https://img.qammunity.org/2019/formulas/mathematics/college/s1h9lll8tuifejm5kobuolpu9wnk82vhwj.png)
Multiplying both sides by 10, we get
![10 * (x)/(10)=10 *(1)/(4)](https://img.qammunity.org/2019/formulas/mathematics/college/sz9qzyyqs5q5gpzjkepwuzk2ojhii68xk4.png)
x=2.50.
Therefore, radius of the small cylinder = 2.5 cm.
Now, plugging radius =2.5 and height = 4 in the formula of volume the cylinder, we get
![V=\pi (2.5)^2(4)=\pi (6.25)(4) =25 \pi \ cm^3.](https://img.qammunity.org/2019/formulas/mathematics/college/ancd5y4xg9nuke98ciz1k3mrjs3ccdcjv3.png)
Therefore, correct option is 25 pi cm^3.