Question

Car a leaves the grand canyon at noon. it travels at 60 mph, but stops at 3 pm for an hour. car b leaves the grand canyon at 2 pm and travels at 70 mph without stopping on the same route as car

a. when does car b catch up with car a

Answer 1

3:30pm .................

Answer 2

Car B catches up with Car A at 3:57 pm.

Step 1: Calculate the distance traveled by Car A before stopping.

Car A travels for 3 hours at 60 mph, so it covers a distance of 3 hours * 60 mph = 180 miles before stopping at 3 pm.

Step 2: Calculate the time it takes for Car B to catch up with Car A.

Car B travels at a speed of 70 mph, so it would take 180 miles / 70 mph = 2.57 hours to catch up with Car A if Car A didn't stop.

Step 3: Adjust the time for Car B to catch up with Car A considering Car A's stop.

Since Car A stops for an hour, Car B will catch up with Car A 2.57 hours - 1 hour = 1.57 hours after 2 pm, which is at 3:57 pm.

Therefore, Car B catches up with Car A at 3:57 pm.