Circle the GCF of 28x³ and 16x²y².

Amitdatta asked Sep 7, 2023

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18 votes

Amitdatta asked Sep 7, 2023

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16 votes

Answer:

4x^(2)

Explanation:

You have to line up all your factors.

$28x^3 =2*2*7*x*x*x\\16x^2y^2=2*2*2*2*x*x*y*y\\$

Isolate what factors they have in common... and solve!

$2*2*x*x\\4*x*x\\4x^2$

Hope this helps!

Pupadupa answered Sep 14, 2023

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