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5 votes
The graph represents the feasible region for the system:

y<=2x
 x + y<=45
x <=30

Minimize the objective function P = 25x + 20y.

The minimum value =?
and occurs when x = ?
and y = ?

2 Answers

5 votes

Answer:

The minimum value =

975

and occurs when x =

15

and y =

30

Explanation:

Edge. 2020

User Goldsky
by
7.5k points
5 votes

We have been given a system of inequalities and an objective function.

The inequalities are given as:


y\leq 2x\\ x+y\leq 45\\ x\leq 30\\

And the objective function is given as:


P=25x+20y

In order to find the minimum value of the objective function at the given feasible region, we need to first graph the region.

The graph of the region is shown below:

From the graph, we can see that corner points of the feasible region are:

(x,y) = (15,30),(30,15) and (30,60).

Now we will evaluate the value of the objective function at each of these corner points and then we will compare which of those values is minimum.


\text{At (15,30)}\Leftrightarrow P=25\cdot 15+20\cdot 30=975\\ \text{At (30,15)}\Leftrightarrow P=25\cdot 30+20\cdot 15=1050\\ \text{At (30,60)}\Leftrightarrow P=25\cdot 30+20\cdot 60=1950\\

Hence the minimum value of objective function is 975 and it occurs at x = 15 and y = 30

The graph represents the feasible region for the system: y<=2x x + y<=45 x &lt-example-1
User Harthoo
by
8.1k points