Question

2x2 + 3x = -1 using the quadratic formula

Answer 1

`{2x}^(2) + 3x = - 1`
add 1 to both sides

`{2x}^(2) + 3x + 1 = 0`
plug in for the formula

`{ax}^(2) + bx + c`

`\frac{ - b + ( - ) \sqrt{ {b}^(2) - 4(a)(c) } }{2(a)}`

`\frac{ - 3 + ( - ) \sqrt{ {3}^(2) - 4(2)(1) }}{2(2)}`
simplify by multiplying and exponents


`( - 3 + ( - ) √( 9 - 8 ))/(4)`
subtract then solve the square root


`( - 3 + ( - ) √( 1))/(4)`

`( - 3 + ( - ) 1)/(4)`
now solve for the plus and minus
(plus):

`( - 3 + 1)/(4)`

`( - 2)/(4) = - 0.5`
(minus):

`( - 3 - 1)/(4)`

`( - 4)/(4) = - 1`
so the answer would be -0.5 and -1

Answer 2

a = 2
b = 3
c = 1

x = [(-b +-sq root (b^2 -4ac)] / 2a
x = [-3 +- sq root (9 - 8) ] / 4
x1= (-3 + 1) / 4 = -.5

x2 = (-3 - 1) / 4 = -1